Base | Representation |
---|---|
bin | 1100000110001110111001… |
… | …1111100101000001100101 |
3 | 1202002120202220002011210202 |
4 | 3001203232133211001211 |
5 | 3220411344310111231 |
6 | 44142255054400245 |
7 | 2541660426365612 |
oct | 301435637450145 |
9 | 52076686064722 |
10 | 13301220003941 |
11 | 4269019a26011 |
12 | 15a9a47800085 |
13 | 7563b849363c |
14 | 33dad51c3509 |
15 | 180edded35cb |
hex | c18ee7e5065 |
13301220003941 has 2 divisors, whose sum is σ = 13301220003942. Its totient is φ = 13301220003940.
The previous prime is 13301220003937. The next prime is 13301220003947. The reversal of 13301220003941 is 14930002210331.
13301220003941 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10464875622916 + 2836344381025 = 3234946^2 + 1684145^2 .
It is a cyclic number.
It is not a de Polignac number, because 13301220003941 - 22 = 13301220003937 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13301220003947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650610001970 + 6650610001971.
It is an arithmetic number, because the mean of its divisors is an integer number (6650610001971).
Almost surely, 213301220003941 is an apocalyptic number.
It is an amenable number.
13301220003941 is a deficient number, since it is larger than the sum of its proper divisors (1).
13301220003941 is an equidigital number, since it uses as much as digits as its factorization.
13301220003941 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 29.
The spelling of 13301220003941 in words is "thirteen trillion, three hundred one billion, two hundred twenty million, three thousand, nine hundred forty-one".
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