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13301221430401 is a prime number
BaseRepresentation
bin1100000110001110111010…
…0101000001010010000001
31202002120202222202122112121
43001203232211001102001
53220411400141233101
644142255145124241
72541660444456442
oct301435645012201
952076688678477
1013301221430401
11426901a80a803
1215a9a48189681
137563b88729b8
1433dad54752c9
15180ede1b60a1
hexc18ee941481

13301221430401 has 2 divisors, whose sum is σ = 13301221430402. Its totient is φ = 13301221430400.

The previous prime is 13301221430389. The next prime is 13301221430423. The reversal of 13301221430401 is 10403412210331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12698852967025 + 602368463376 = 3563545^2 + 776124^2 .

It is a cyclic number.

It is not a de Polignac number, because 13301221430401 - 241 = 11102198174849 is a prime.

It is not a weakly prime, because it can be changed into another prime (13301221430461) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650610715200 + 6650610715201.

It is an arithmetic number, because the mean of its divisors is an integer number (6650610715201).

Almost surely, 213301221430401 is an apocalyptic number.

It is an amenable number.

13301221430401 is a deficient number, since it is larger than the sum of its proper divisors (1).

13301221430401 is an equidigital number, since it uses as much as digits as its factorization.

13301221430401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13301221430401 its reverse (10403412210331), we get a palindrome (23704633640732).

The spelling of 13301221430401 in words is "thirteen trillion, three hundred one billion, two hundred twenty-one million, four hundred thirty thousand, four hundred one".