Base | Representation |
---|---|
bin | 10011010110110001011… |
… | …101100110110111110101 |
3 | 11201011021111121221011111 |
4 | 103112301131212313311 |
5 | 133243042242114333 |
6 | 2455014423235021 |
7 | 165045445230646 |
oct | 23266135466765 |
9 | 4634244557144 |
10 | 1330122223093 |
11 | 473113356244 |
12 | 1959532a8a71 |
13 | 985788b42a1 |
14 | 48541d2b6cd |
15 | 248ed6434cd |
hex | 135b1766df5 |
1330122223093 has 2 divisors, whose sum is σ = 1330122223094. Its totient is φ = 1330122223092.
The previous prime is 1330122223049. The next prime is 1330122223139. The reversal of 1330122223093 is 3903222210331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1328666571684 + 1455651409 = 1152678^2 + 38153^2 .
It is an emirp because it is prime and its reverse (3903222210331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1330122223093 - 213 = 1330122214901 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1330122223033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665061111546 + 665061111547.
It is an arithmetic number, because the mean of its divisors is an integer number (665061111547).
Almost surely, 21330122223093 is an apocalyptic number.
It is an amenable number.
1330122223093 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330122223093 is an equidigital number, since it uses as much as digits as its factorization.
1330122223093 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11664, while the sum is 31.
The spelling of 1330122223093 in words is "one trillion, three hundred thirty billion, one hundred twenty-two million, two hundred twenty-three thousand, ninety-three".
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