Base | Representation |
---|---|
bin | 10011010110110001111… |
… | …111111001100000100011 |
3 | 11201011022010112122001221 |
4 | 103112301333321200203 |
5 | 133243102042243243 |
6 | 2455015344035511 |
7 | 165045614520424 |
oct | 23266177714043 |
9 | 4634263478057 |
10 | 1330131212323 |
11 | 473118435a61 |
12 | 195956302b97 |
13 | 9857a710a64 |
14 | 485431cb64b |
15 | 248ee31bbed |
hex | 135b1ff9823 |
1330131212323 has 2 divisors, whose sum is σ = 1330131212324. Its totient is φ = 1330131212322.
The previous prime is 1330131212257. The next prime is 1330131212383. The reversal of 1330131212323 is 3232121310331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1330131212323 is a prime.
It is not a weakly prime, because it can be changed into another prime (1330131212383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665065606161 + 665065606162.
It is an arithmetic number, because the mean of its divisors is an integer number (665065606162).
Almost surely, 21330131212323 is an apocalyptic number.
1330131212323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330131212323 is an equidigital number, since it uses as much as digits as its factorization.
1330131212323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 1330131212323 its reverse (3232121310331), we get a palindrome (4562252522654).
The spelling of 1330131212323 in words is "one trillion, three hundred thirty billion, one hundred thirty-one million, two hundred twelve thousand, three hundred twenty-three".
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