Base | Representation |
---|---|
bin | 111101111100000110… |
… | …1001101000110100101 |
3 | 110201022220212012002112 |
4 | 1323320031031012211 |
5 | 4134402341324424 |
6 | 141034435050405 |
7 | 12416122541303 |
oct | 1737015150645 |
9 | 421286765075 |
10 | 133013229989 |
11 | 51457556452 |
12 | 21941a40a05 |
13 | c70a23bb63 |
14 | 661b757273 |
15 | 36d766c60e |
hex | 1ef834d1a5 |
133013229989 has 2 divisors, whose sum is σ = 133013229990. Its totient is φ = 133013229988.
The previous prime is 133013229977. The next prime is 133013230019. The reversal of 133013229989 is 989922310331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 127568265889 + 5444964100 = 357167^2 + 73790^2 .
It is an emirp because it is prime and its reverse (989922310331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133013229989 - 212 = 133013225893 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133013229389) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66506614994 + 66506614995.
It is an arithmetic number, because the mean of its divisors is an integer number (66506614995).
Almost surely, 2133013229989 is an apocalyptic number.
It is an amenable number.
133013229989 is a deficient number, since it is larger than the sum of its proper divisors (1).
133013229989 is an equidigital number, since it uses as much as digits as its factorization.
133013229989 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 629856, while the sum is 50.
The spelling of 133013229989 in words is "one hundred thirty-three billion, thirteen million, two hundred twenty-nine thousand, nine hundred eighty-nine".
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