Base | Representation |
---|---|
bin | 1100000110001111010010… |
… | …1000111001111010101111 |
3 | 1202002121001002002121121212 |
4 | 3001203310220321322233 |
5 | 3220412102204041421 |
6 | 44142313220345035 |
7 | 2541663120654536 |
oct | 301436450717257 |
9 | 52077032077555 |
10 | 13301323112111 |
11 | 426907214a781 |
12 | 15a9a7624517b |
13 | 756403954aa8 |
14 | 33db04b8331d |
15 | 180ee809de5b |
hex | c18f4a39eaf |
13301323112111 has 2 divisors, whose sum is σ = 13301323112112. Its totient is φ = 13301323112110.
The previous prime is 13301323112087. The next prime is 13301323112159. The reversal of 13301323112111 is 11121132310331.
It is a weak prime.
It is an emirp because it is prime and its reverse (11121132310331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13301323112111 - 226 = 13301256003247 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13301323112711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650661556055 + 6650661556056.
It is an arithmetic number, because the mean of its divisors is an integer number (6650661556056).
Almost surely, 213301323112111 is an apocalyptic number.
13301323112111 is a deficient number, since it is larger than the sum of its proper divisors (1).
13301323112111 is an equidigital number, since it uses as much as digits as its factorization.
13301323112111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 13301323112111 its reverse (11121132310331), we get a palindrome (24422455422442).
The spelling of 13301323112111 in words is "thirteen trillion, three hundred one billion, three hundred twenty-three million, one hundred twelve thousand, one hundred eleven".
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