Base | Representation |
---|---|
bin | 1100000110001111010110… |
… | …1001110111001100001110 |
3 | 1202002121002021010201220121 |
4 | 3001203311221313030032 |
5 | 3220412121033442202 |
6 | 44142315025335154 |
7 | 2541663415465444 |
oct | 301436551671416 |
9 | 52077067121817 |
10 | 13301340140302 |
11 | 4269080820265 |
12 | 15a9a7ba974ba |
13 | 756407337646 |
14 | 33db07136b94 |
15 | 180ee9814537 |
hex | c18f5a7730e |
13301340140302 has 4 divisors (see below), whose sum is σ = 19952010210456. Its totient is φ = 6650670070150.
The previous prime is 13301340140287. The next prime is 13301340140311. The reversal of 13301340140302 is 20304104310331.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3325335035074 + ... + 3325335035077.
It is an arithmetic number, because the mean of its divisors is an integer number (4988002552614).
Almost surely, 213301340140302 is an apocalyptic number.
13301340140302 is a deficient number, since it is larger than the sum of its proper divisors (6650670070154).
13301340140302 is an equidigital number, since it uses as much as digits as its factorization.
13301340140302 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6650670070153.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 13301340140302 its reverse (20304104310331), we get a palindrome (33605444450633).
The spelling of 13301340140302 in words is "thirteen trillion, three hundred one billion, three hundred forty million, one hundred forty thousand, three hundred two".
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