133020402001333 has 32 divisors (see below), whose sum is σ = 169900402065408. Its totient is φ = 101117123030400.

The previous prime is 133020402001309. The next prime is 133020402001373. The reversal of 133020402001333 is 333100204020331.

It is a cyclic number.

It is not a de Polignac number, because 133020402001333 - 2⁹ = 133020402000821 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133020402001298 and 133020402001307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133020402001373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 44150916 + ... + 47067442.

It is an arithmetic number, because the mean of its divisors is an integer number (5309387564544).

Almost surely, 2^{133020402001333} is an apocalyptic number.

It is an amenable number.

133020402001333 is a deficient number, since it is larger than the sum of its proper divisors (36880000064075).

133020402001333 is a wasteful number, since it uses less digits than its factorization.

133020402001333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2931033.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 133020402001333 its reverse (333100204020331), we get a palindrome (466120606021664).

The spelling of 133020402001333 in words is "one hundred thirty-three trillion, twenty billion, four hundred two million, one thousand, three hundred thirty-three".