Base | Representation |
---|---|
bin | 11110001111101101000010… |
… | …000011100110101100110111 |
3 | 122102222122021011121020202021 |
4 | 132033231002003212230313 |
5 | 114413402031313144443 |
6 | 1150524443112454011 |
7 | 40006262665166461 |
oct | 3617550203465467 |
9 | 572878234536667 |
10 | 133020540365623 |
11 | 3942577021a689 |
12 | 12b043319aa307 |
13 | 592ba24708b91 |
14 | 24bc32b03d131 |
15 | 105a2821e69ed |
hex | 78fb420e6b37 |
133020540365623 has 2 divisors, whose sum is σ = 133020540365624. Its totient is φ = 133020540365622.
The previous prime is 133020540365567. The next prime is 133020540365627. The reversal of 133020540365623 is 326563045020331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133020540365623 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 133020540365623.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133020540365627) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66510270182811 + 66510270182812.
It is an arithmetic number, because the mean of its divisors is an integer number (66510270182812).
Almost surely, 2133020540365623 is an apocalyptic number.
133020540365623 is a deficient number, since it is larger than the sum of its proper divisors (1).
133020540365623 is an equidigital number, since it uses as much as digits as its factorization.
133020540365623 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1166400, while the sum is 43.
Adding to 133020540365623 its reverse (326563045020331), we get a palindrome (459583585385954).
The spelling of 133020540365623 in words is "one hundred thirty-three trillion, twenty billion, five hundred forty million, three hundred sixty-five thousand, six hundred twenty-three".
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