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133020540365623 is a prime number
BaseRepresentation
bin11110001111101101000010…
…000011100110101100110111
3122102222122021011121020202021
4132033231002003212230313
5114413402031313144443
61150524443112454011
740006262665166461
oct3617550203465467
9572878234536667
10133020540365623
113942577021a689
1212b043319aa307
13592ba24708b91
1424bc32b03d131
15105a2821e69ed
hex78fb420e6b37

133020540365623 has 2 divisors, whose sum is σ = 133020540365624. Its totient is φ = 133020540365622.

The previous prime is 133020540365567. The next prime is 133020540365627. The reversal of 133020540365623 is 326563045020331.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133020540365623 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 133020540365623.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133020540365627) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66510270182811 + 66510270182812.

It is an arithmetic number, because the mean of its divisors is an integer number (66510270182812).

Almost surely, 2133020540365623 is an apocalyptic number.

133020540365623 is a deficient number, since it is larger than the sum of its proper divisors (1).

133020540365623 is an equidigital number, since it uses as much as digits as its factorization.

133020540365623 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1166400, while the sum is 43.

Adding to 133020540365623 its reverse (326563045020331), we get a palindrome (459583585385954).

The spelling of 133020540365623 in words is "one hundred thirty-three trillion, twenty billion, five hundred forty million, three hundred sixty-five thousand, six hundred twenty-three".