Base | Representation |
---|---|
bin | 11110001111101101101010… |
… | …111001011000010101111110 |
3 | 122102222201000220220021200222 |
4 | 132033231222321120111332 |
5 | 114413404432220114410 |
6 | 1150525035110421342 |
7 | 40006315655160242 |
oct | 3617555271302576 |
9 | 572881026807628 |
10 | 133021225551230 |
11 | 39425a91a70785 |
12 | 12b044a3361852 |
13 | 592bb0365c253 |
14 | 24bc39403c422 |
15 | 105a2c243e955 |
hex | 78fb6ae5857e |
133021225551230 has 16 divisors (see below), whose sum is σ = 239438746856880. Its totient is φ = 53208370028352.
The previous prime is 133021225551223. The next prime is 133021225551233. The reversal of 133021225551230 is 32155522120331.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133021225551233) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10305140 + ... + 19293479.
It is an arithmetic number, because the mean of its divisors is an integer number (14964921678555).
Almost surely, 2133021225551230 is an apocalyptic number.
133021225551230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
133021225551230 is a deficient number, since it is larger than the sum of its proper divisors (106417521305650).
133021225551230 is a wasteful number, since it uses less digits than its factorization.
133021225551230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30048043.
The product of its (nonzero) digits is 54000, while the sum is 35.
Adding to 133021225551230 its reverse (32155522120331), we get a palindrome (165176747671561).
The spelling of 133021225551230 in words is "one hundred thirty-three trillion, twenty-one billion, two hundred twenty-five million, five hundred fifty-one thousand, two hundred thirty".
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