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13302243441044 = 225099652198639
BaseRepresentation
bin1100000110010010101101…
…1111101011100110010100
31202002200102012212011120122
43001210223133223212110
53220420443310103134
644142544414251112
72542024664432345
oct301445337534624
952080365764518
1013302243441044
1142694a46a74a8
1215aa0924b6a98
1375651c51851c
1433db910b20cc
1518104dc9402e
hexc192b7eb994

13302243441044 has 12 divisors (see below), whose sum is σ = 23283491448000. Its totient is φ = 6649817313048.

The previous prime is 13302243440989. The next prime is 13302243441073. The reversal of 13302243441044 is 44014434220331.

It is a junction number, because it is equal to n+sod(n) for n = 13302243440995 and 13302243441013.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 326078924 + ... + 326119715.

It is an arithmetic number, because the mean of its divisors is an integer number (1940290954000).

Almost surely, 213302243441044 is an apocalyptic number.

It is an amenable number.

13302243441044 is a deficient number, since it is larger than the sum of its proper divisors (9981248006956).

13302243441044 is a wasteful number, since it uses less digits than its factorization.

13302243441044 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 652203742 (or 652203740 counting only the distinct ones).

The product of its (nonzero) digits is 110592, while the sum is 35.

Adding to 13302243441044 its reverse (44014434220331), we get a palindrome (57316677661375).

The spelling of 13302243441044 in words is "thirteen trillion, three hundred two billion, two hundred forty-three million, four hundred forty-one thousand, forty-four".

Divisors: 1 2 4 5099 10198 20396 652198639 1304397278 2608794556 3325560860261 6651121720522 13302243441044