Base | Representation |
---|---|
bin | 11110001111101111011101… |
… | …101010110110101111001011 |
3 | 122102222220000010012111010212 |
4 | 132033233131222312233023 |
5 | 114413422403141422103 |
6 | 1150525554134231335 |
7 | 40006414456234262 |
oct | 3617573552665713 |
9 | 572886003174125 |
10 | 133023151123403 |
11 | 3942688a9a2642 |
12 | 12b049401b554b |
13 | 592c04c577578 |
14 | 24bc4d7a815d9 |
15 | 105a3864ee7d8 |
hex | 78fbddab6bcb |
133023151123403 has 2 divisors, whose sum is σ = 133023151123404. Its totient is φ = 133023151123402.
The previous prime is 133023151123397. The next prime is 133023151123427. The reversal of 133023151123403 is 304321151320331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133023151123403 - 212 = 133023151119307 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 133023151123403.
It is not a weakly prime, because it can be changed into another prime (133023151123453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66511575561701 + 66511575561702.
It is an arithmetic number, because the mean of its divisors is an integer number (66511575561702).
Almost surely, 2133023151123403 is an apocalyptic number.
133023151123403 is a deficient number, since it is larger than the sum of its proper divisors (1).
133023151123403 is an equidigital number, since it uses as much as digits as its factorization.
133023151123403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19440, while the sum is 32.
The spelling of 133023151123403 in words is "one hundred thirty-three trillion, twenty-three billion, one hundred fifty-one million, one hundred twenty-three thousand, four hundred three".
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