Base | Representation |
---|---|
bin | 111101111100011010… |
… | …0000101101100010011 |
3 | 110201100122001001121202 |
4 | 1323320310011230103 |
5 | 4134412444021001 |
6 | 141035441341415 |
7 | 12416305304255 |
oct | 1737064055423 |
9 | 421318031552 |
10 | 133023423251 |
11 | 51462288834 |
12 | 2194533786b |
13 | c70c39a684 |
14 | 661cc4bcd5 |
15 | 36d84d296b |
hex | 1ef8d05b13 |
133023423251 has 2 divisors, whose sum is σ = 133023423252. Its totient is φ = 133023423250.
The previous prime is 133023423193. The next prime is 133023423289. The reversal of 133023423251 is 152324320331.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (152324320331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133023423251 - 218 = 133023161107 is a prime.
It is a super-2 number, since 2×1330234232512 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (133023423151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66511711625 + 66511711626.
It is an arithmetic number, because the mean of its divisors is an integer number (66511711626).
Almost surely, 2133023423251 is an apocalyptic number.
133023423251 is a deficient number, since it is larger than the sum of its proper divisors (1).
133023423251 is an equidigital number, since it uses as much as digits as its factorization.
133023423251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 29.
Adding to 133023423251 its reverse (152324320331), we get a palindrome (285347743582).
The spelling of 133023423251 in words is "one hundred thirty-three billion, twenty-three million, four hundred twenty-three thousand, two hundred fifty-one".
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