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133024424014439 is a prime number
BaseRepresentation
bin11110001111110000101001…
…100010100011001001100111
3122110000000021211101001101022
4132033300221202203021213
5114413433010021430224
61150530324324521355
740006461143516666
oct3617605142431147
9573000254331338
10133024424014439
1139427383464501
1212b0503655025b
13592c1c31b0429
1424bc5b8b46ddd
15105a40d13765e
hex78fc298a3267

133024424014439 has 2 divisors, whose sum is σ = 133024424014440. Its totient is φ = 133024424014438.

The previous prime is 133024424014369. The next prime is 133024424014453. The reversal of 133024424014439 is 934410424420331.

It is a strong prime.

It is an emirp because it is prime and its reverse (934410424420331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133024424014439 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 133024424014439.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133024424014459) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66512212007219 + 66512212007220.

It is an arithmetic number, because the mean of its divisors is an integer number (66512212007220).

Almost surely, 2133024424014439 is an apocalyptic number.

133024424014439 is a deficient number, since it is larger than the sum of its proper divisors (1).

133024424014439 is an equidigital number, since it uses as much as digits as its factorization.

133024424014439 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 995328, while the sum is 44.

The spelling of 133024424014439 in words is "one hundred thirty-three trillion, twenty-four billion, four hundred twenty-four million, fourteen thousand, four hundred thirty-nine".