1330251017 has 2 divisors, whose sum is σ = 1330251018. Its totient is φ = 1330251016.

The previous prime is 1330251007. The next prime is 1330251019. The reversal of 1330251017 is 7101520331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1300395721 + 29855296 = 36061^2 + 5464^2 .

It is a cyclic number.

It is not a de Polignac number, because 1330251017 - 2⁴ = 1330251001 is a prime.

Together with 1330251019, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1330250983 and 1330251001.

It is not a weakly prime, because it can be changed into another prime (1330251019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665125508 + 665125509.

It is an arithmetic number, because the mean of its divisors is an integer number (665125509).

Almost surely, 2^1330251017 is an apocalyptic number.

It is an amenable number.

1330251017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330251017 is an equidigital number, since it uses as much as digits as its factorization.

1330251017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 630, while the sum is 23.

The square root of 1330251017 is about 36472.6063916469. The cubic root of 1330251017 is about 1099.7936298805.

Adding to 1330251017 its reverse (7101520331), we get a palindrome (8431771348).

The spelling of 1330251017 in words is "one billion, three hundred thirty million, two hundred fifty-one thousand, seventeen".