133025334461413 has 2 divisors, whose sum is σ = 133025334461414. Its totient is φ = 133025334461412.

The previous prime is 133025334461387. The next prime is 133025334461431. The reversal of 133025334461413 is 314164433520331.

Together with next prime (133025334461431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111641581659364 + 21383752802049 = 10566058^2 + 4624257^2 .

It is an emirp because it is prime and its reverse (314164433520331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133025334461413 - 2³³ = 133016744526821 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 133025334461413.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133025334461113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66512667230706 + 66512667230707.

It is an arithmetic number, because the mean of its divisors is an integer number (66512667230707).

Almost surely, 2^{133025334461413} is an apocalyptic number.

It is an amenable number.

133025334461413 is a deficient number, since it is larger than the sum of its proper divisors (1).

133025334461413 is an equidigital number, since it uses as much as digits as its factorization.

133025334461413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 933120, while the sum is 43.

Adding to 133025334461413 its reverse (314164433520331), we get a palindrome (447189767981744).

The spelling of 133025334461413 in words is "one hundred thirty-three trillion, twenty-five billion, three hundred thirty-four million, four hundred sixty-one thousand, four hundred thirteen".