Base | Representation |
---|---|
bin | 100111101001010… |
… | …0001100010101111 |
3 | 10102201010000020111 |
4 | 1033102201202233 |
5 | 10211021143142 |
6 | 340000000451 |
7 | 44651663341 |
oct | 11722414257 |
9 | 3381100214 |
10 | 1330256047 |
11 | 62299306a |
12 | 311600127 |
13 | 18279c673 |
14 | c8959291 |
15 | 7bbb9e17 |
hex | 4f4a18af |
1330256047 has 2 divisors, whose sum is σ = 1330256048. Its totient is φ = 1330256046.
The previous prime is 1330255921. The next prime is 1330256099. The reversal of 1330256047 is 7406520331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1330256047 - 27 = 1330255919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1330256947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665128023 + 665128024.
It is an arithmetic number, because the mean of its divisors is an integer number (665128024).
Almost surely, 21330256047 is an apocalyptic number.
1330256047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330256047 is an equidigital number, since it uses as much as digits as its factorization.
1330256047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 31.
The square root of 1330256047 is about 36472.6753474433. The cubic root of 1330256047 is about 1099.7950160738.
Adding to 1330256047 its reverse (7406520331), we get a palindrome (8736776378).
The spelling of 1330256047 in words is "one billion, three hundred thirty million, two hundred fifty-six thousand, forty-seven".
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