Search a number
-
+
133026011121324 = 22311085500926777
BaseRepresentation
bin11110001111110010001000…
…001000111000011010101100
3122110000011101102210102201210
4132033302020020320122230
5114413444232321340244
61150531150022034420
740006545364640526
oct3617621010703254
9573004342712653
10133026011121324
113942801832a392
1212b053b9b78a10
13592c3b6c50829
1424bc6c9842a16
15105a4a263b4b9
hex78fc882386ac

133026011121324 has 12 divisors (see below), whose sum is σ = 310394025949784. Its totient is φ = 44342003707104.

The previous prime is 133026011121317. The next prime is 133026011121383. The reversal of 133026011121324 is 423121110620331.

It is a tau number, because it is divible by the number of its divisors (12).

It is a junction number, because it is equal to n+sod(n) for n = 133026011121291 and 133026011121300.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5542750463377 + ... + 5542750463400.

Almost surely, 2133026011121324 is an apocalyptic number.

It is an amenable number.

133026011121324 is an abundant number, since it is smaller than the sum of its proper divisors (177368014828460).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133026011121324 is a wasteful number, since it uses less digits than its factorization.

133026011121324 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11085500926784 (or 11085500926782 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 30.

Adding to 133026011121324 its reverse (423121110620331), we get a palindrome (556147121741655).

The spelling of 133026011121324 in words is "one hundred thirty-three trillion, twenty-six billion, eleven million, one hundred twenty-one thousand, three hundred twenty-four".

Divisors: 1 2 3 4 6 12 11085500926777 22171001853554 33256502780331 44342003707108 66513005560662 133026011121324