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1330303040034 = 23172767187451
BaseRepresentation
bin10011010110111100001…
…111010111101000100010
311201011202002212101101020
4103112330033113220202
5133243430034240114
62455044402550310
7165053102161023
oct23267417275042
94634662771336
101330303040034
114731a6426731
121959a3968396
13985a71b2c67
144855bd58c4a
152490e45daa9
hex135bc3d7a22

1330303040034 has 24 divisors (see below), whose sum is σ = 2826318573168. Its totient is φ = 417349972800.

The previous prime is 1330303039979. The next prime is 1330303040039. The reversal of 1330303040034 is 4300403030331.

It is a junction number, because it is equal to n+sod(n) for n = 1330303039986 and 1330303040013.

It is not an unprimeable number, because it can be changed into a prime (1330303040039) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 383591992 + ... + 383595459.

It is an arithmetic number, because the mean of its divisors is an integer number (117763273882).

Almost surely, 21330303040034 is an apocalyptic number.

1330303040034 is an abundant number, since it is smaller than the sum of its proper divisors (1496015533134).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1330303040034 is a wasteful number, since it uses less digits than its factorization.

1330303040034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 767187490 (or 767187473 counting only the distinct ones).

The product of its (nonzero) digits is 3888, while the sum is 24.

Adding to 1330303040034 its reverse (4300403030331), we get a palindrome (5630706070365).

The spelling of 1330303040034 in words is "one trillion, three hundred thirty billion, three hundred three million, forty thousand, thirty-four".

Divisors: 1 2 3 6 17 34 51 102 289 578 867 1734 767187451 1534374902 2301562353 4603124706 13042186667 26084373334 39126560001 78253120002 221717173339 443434346678 665151520017 1330303040034