Base | Representation |
---|---|
bin | 10011010110111100001… |
… | …111010111101001110000 |
3 | 11201011202002212101111010 |
4 | 103112330033113221300 |
5 | 133243430034240422 |
6 | 2455044402550520 |
7 | 165053102161164 |
oct | 23267417275160 |
9 | 4634662771433 |
10 | 1330303040112 |
11 | 4731a64267a2 |
12 | 1959a3968440 |
13 | 985a71b2cc7 |
14 | 4855bd58ca4 |
15 | 2490e45db0c |
hex | 135bc3d7a70 |
1330303040112 has 40 divisors (see below), whose sum is σ = 3450307916160. Its totient is φ = 441667672000.
The previous prime is 1330303040111. The next prime is 1330303040117. The reversal of 1330303040112 is 2110403030331.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1330303040111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 55196412 + ... + 55220507.
It is an arithmetic number, because the mean of its divisors is an integer number (86257697904).
Almost surely, 21330303040112 is an apocalyptic number.
1330303040112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1330303040112 is an abundant number, since it is smaller than the sum of its proper divisors (2120004876048).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1330303040112 is a wasteful number, since it uses less digits than its factorization.
1330303040112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 110417181 (or 110417175 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 1330303040112 its reverse (2110403030331), we get a palindrome (3440706070443).
The spelling of 1330303040112 in words is "one trillion, three hundred thirty billion, three hundred three million, forty thousand, one hundred twelve".
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