Base | Representation |
---|---|
bin | 111101111100101000… |
… | …1011011000111000001 |
3 | 110201101011111202011221 |
4 | 1323321101123013001 |
5 | 4134421431110103 |
6 | 141040314235041 |
7 | 12416430542641 |
oct | 1737121330701 |
9 | 421334452157 |
10 | 133031113153 |
11 | 51466660324 |
12 | 21947a25a81 |
13 | c710b60903 |
14 | 661dc90521 |
15 | 36d90011bd |
hex | 1ef945b1c1 |
133031113153 has 2 divisors, whose sum is σ = 133031113154. Its totient is φ = 133031113152.
The previous prime is 133031113141. The next prime is 133031113157. The reversal of 133031113153 is 351311130331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 105450871824 + 27580241329 = 324732^2 + 166073^2 .
It is a cyclic number.
It is not a de Polignac number, because 133031113153 - 225 = 132997558721 is a prime.
It is not a weakly prime, because it can be changed into another prime (133031113157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66515556576 + 66515556577.
It is an arithmetic number, because the mean of its divisors is an integer number (66515556577).
Almost surely, 2133031113153 is an apocalyptic number.
It is an amenable number.
133031113153 is a deficient number, since it is larger than the sum of its proper divisors (1).
133031113153 is an equidigital number, since it uses as much as digits as its factorization.
133031113153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1215, while the sum is 25.
Adding to 133031113153 its reverse (351311130331), we get a palindrome (484342243484).
The spelling of 133031113153 in words is "one hundred thirty-three billion, thirty-one million, one hundred thirteen thousand, one hundred fifty-three".
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