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13303112113 is a prime number
BaseRepresentation
bin11000110001110110…
…10110000110110001
31021100010011010010001
430120323112012301
5204221044041423
610040015510001
7650443405264
oct143073260661
937303133101
1013303112113
115707295035
1226b3228301
13134011c195
14902b0ccdb
1552cd77cad
hex318ed61b1

13303112113 has 2 divisors, whose sum is σ = 13303112114. Its totient is φ = 13303112112.

The previous prime is 13303112111. The next prime is 13303112129. The reversal of 13303112113 is 31121130331.

13303112113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9838259344 + 3464852769 = 99188^2 + 58863^2 .

It is a cyclic number.

It is not a de Polignac number, because 13303112113 - 21 = 13303112111 is a prime.

Together with 13303112111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13303112111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6651556056 + 6651556057.

It is an arithmetic number, because the mean of its divisors is an integer number (6651556057).

Almost surely, 213303112113 is an apocalyptic number.

It is an amenable number.

13303112113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13303112113 is an equidigital number, since it uses as much as digits as its factorization.

13303112113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 13303112113 its reverse (31121130331), we get a palindrome (44424242444).

The spelling of 13303112113 in words is "thirteen billion, three hundred three million, one hundred twelve thousand, one hundred thirteen".