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13303124111 is a prime number
BaseRepresentation
bin11000110001110110…
…11001000010001111
31021100010011201120102
430120323121002033
5204221044432421
610040020041315
7650443455254
oct143073310217
937303151512
1013303124111
1157072a3052
1226b323323b
131340124794
14902b1342b
1552cd7b60b
hex318ed908f

13303124111 has 2 divisors, whose sum is σ = 13303124112. Its totient is φ = 13303124110.

The previous prime is 13303124101. The next prime is 13303124119. The reversal of 13303124111 is 11142130331.

13303124111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13303124111 is a prime.

It is a super-2 number, since 2×133031241112 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13303124119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6651562055 + 6651562056.

It is an arithmetic number, because the mean of its divisors is an integer number (6651562056).

Almost surely, 213303124111 is an apocalyptic number.

13303124111 is a deficient number, since it is larger than the sum of its proper divisors (1).

13303124111 is an equidigital number, since it uses as much as digits as its factorization.

13303124111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 13303124111 its reverse (11142130331), we get a palindrome (24445254442).

The spelling of 13303124111 in words is "thirteen billion, three hundred three million, one hundred twenty-four thousand, one hundred eleven".