Base | Representation |
---|---|
bin | 111101111100101011… |
… | …0011000010100010111 |
3 | 110201101020221202110122 |
4 | 1323321112120110113 |
5 | 4134422244144224 |
6 | 141040402142155 |
7 | 12416444563643 |
oct | 1737126302427 |
9 | 421336852418 |
10 | 133032412439 |
11 | 51467368513 |
12 | 2194835195b |
13 | c7111c7114 |
14 | 662010bc23 |
15 | 36d91ab15e |
hex | 1ef9598517 |
133032412439 has 2 divisors, whose sum is σ = 133032412440. Its totient is φ = 133032412438.
The previous prime is 133032412411. The next prime is 133032412451. The reversal of 133032412439 is 934214230331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133032412439 - 220 = 133031363863 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133032412399 and 133032412408.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133032412489) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66516206219 + 66516206220.
It is an arithmetic number, because the mean of its divisors is an integer number (66516206220).
Almost surely, 2133032412439 is an apocalyptic number.
133032412439 is a deficient number, since it is larger than the sum of its proper divisors (1).
133032412439 is an equidigital number, since it uses as much as digits as its factorization.
133032412439 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 46656, while the sum is 35.
The spelling of 133032412439 in words is "one hundred thirty-three billion, thirty-two million, four hundred twelve thousand, four hundred thirty-nine".
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