Base | Representation |
---|---|
bin | 11110001111111000101111… |
… | …011100110100101001100011 |
3 | 122110000211201101102220020121 |
4 | 132033320233130310221203 |
5 | 114414103303424024024 |
6 | 1150534322442221111 |
7 | 40010216362600303 |
oct | 3617705734645143 |
9 | 573024641386217 |
10 | 133033113111139 |
11 | 3943003220445a |
12 | 12b068604b4797 |
13 | 592cc79415b77 |
14 | 24bcba0b4b603 |
15 | 105a76ad9e8e4 |
hex | 78fe2f734a63 |
133033113111139 has 2 divisors, whose sum is σ = 133033113111140. Its totient is φ = 133033113111138.
The previous prime is 133033113111037. The next prime is 133033113111277. The reversal of 133033113111139 is 931111311330331.
It is a weak prime.
It is an emirp because it is prime and its reverse (931111311330331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133033113111139 - 227 = 133032978893411 is a prime.
It is a super-2 number, since 2×1330331131111392 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (133033113111539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66516556555569 + 66516556555570.
It is an arithmetic number, because the mean of its divisors is an integer number (66516556555570).
Almost surely, 2133033113111139 is an apocalyptic number.
133033113111139 is a deficient number, since it is larger than the sum of its proper divisors (1).
133033113111139 is an equidigital number, since it uses as much as digits as its factorization.
133033113111139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6561, while the sum is 34.
The spelling of 133033113111139 in words is "one hundred thirty-three trillion, thirty-three billion, one hundred thirteen million, one hundred eleven thousand, one hundred thirty-nine".
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