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13303313333113 is a prime number
BaseRepresentation
bin1100000110010110101101…
…0000111111101101111001
31202002210011210001022120211
43001211223100333231321
53220430141203124423
644143242513551121
72542063335400246
oct301455320775571
952083153038524
1013303313333113
1142699a3618221
1215aa3308754a1
1375666008705b
1433dc532145cd
151810b2b7e10d
hexc196b43fb79

13303313333113 has 2 divisors, whose sum is σ = 13303313333114. Its totient is φ = 13303313333112.

The previous prime is 13303313333027. The next prime is 13303313333117. The reversal of 13303313333113 is 31133331330331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6908549641744 + 6394763691369 = 2628412^2 + 2528787^2 .

It is an emirp because it is prime and its reverse (31133331330331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13303313333113 is a prime.

It is not a weakly prime, because it can be changed into another prime (13303313333117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6651656666556 + 6651656666557.

It is an arithmetic number, because the mean of its divisors is an integer number (6651656666557).

Almost surely, 213303313333113 is an apocalyptic number.

It is an amenable number.

13303313333113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13303313333113 is an equidigital number, since it uses as much as digits as its factorization.

13303313333113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19683, while the sum is 31.

Adding to 13303313333113 its reverse (31133331330331), we get a palindrome (44436644663444).

The spelling of 13303313333113 in words is "thirteen trillion, three hundred three billion, three hundred thirteen million, three hundred thirty-three thousand, one hundred thirteen".