Base | Representation |
---|---|
bin | 1100000110010110101101… |
… | …0000111111101101111010 |
3 | 1202002210011210001022120212 |
4 | 3001211223100333231322 |
5 | 3220430141203124424 |
6 | 44143242513551122 |
7 | 2542063335400250 |
oct | 301455320775572 |
9 | 52083153038525 |
10 | 13303313333114 |
11 | 42699a3618222 |
12 | 15aa3308754a2 |
13 | 75666008705c |
14 | 33dc532145d0 |
15 | 1810b2b7e10e |
hex | c196b43fb7a |
13303313333114 has 8 divisors (see below), whose sum is σ = 22805679999648. Its totient is φ = 5701419999900.
The previous prime is 13303313333113. The next prime is 13303313333117. The reversal of 13303313333114 is 41133331330331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not an unprimeable number, because it can be changed into a prime (13303313333113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 475118333312 + ... + 475118333339.
It is an arithmetic number, because the mean of its divisors is an integer number (2850709999956).
Almost surely, 213303313333114 is an apocalyptic number.
13303313333114 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
13303313333114 is a deficient number, since it is larger than the sum of its proper divisors (9502366666534).
13303313333114 is an equidigital number, since it uses as much as digits as its factorization.
13303313333114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 950236666660.
The product of its (nonzero) digits is 26244, while the sum is 32.
Adding to 13303313333114 its reverse (41133331330331), we get a palindrome (54436644663445).
The spelling of 13303313333114 in words is "thirteen trillion, three hundred three billion, three hundred thirteen million, three hundred thirty-three thousand, one hundred fourteen".
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