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1330334402124 = 2237213237935323
BaseRepresentation
bin10011010110111110000…
…111000000011001001100
311201011211021212202002010
4103112332013000121030
5133244011101331444
62455051443101220
7165053632561500
oct23267607003114
94634737782063
101330334402124
114732120a7512
121959b2371810
13985b0843c00
14485621a0300
15249120a62b9
hex135be1c064c

1330334402124 has 216 divisors, whose sum is σ = 3920463812160. Its totient is φ = 349921772928.

The previous prime is 1330334402123. The next prime is 1330334402149. The reversal of 1330334402124 is 4212044330331.

It is a happy number.

It is a super-2 number, since 2×13303344021242 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1330334402091 and 1330334402100.

It is not an unprimeable number, because it can be changed into a prime (1330334402123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 37644327 + ... + 37679649.

Almost surely, 21330334402124 is an apocalyptic number.

1330334402124 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1330334402124, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1960231906080).

1330334402124 is an abundant number, since it is smaller than the sum of its proper divisors (2590129410036).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1330334402124 is a wasteful number, since it uses less digits than its factorization.

1330334402124 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35749 (or 35727 counting only the distinct ones).

The product of its (nonzero) digits is 20736, while the sum is 30.

Adding to 1330334402124 its reverse (4212044330331), we get a palindrome (5542378732455).

The spelling of 1330334402124 in words is "one trillion, three hundred thirty billion, three hundred thirty-four million, four hundred two thousand, one hundred twenty-four".