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133034331014411 is a prime number
BaseRepresentation
bin11110001111111001111000…
…000010110000010100001011
3122110000221212021010210110012
4132033321320002300110023
5114414113302214430121
61150535043350142135
740010261511602561
oct3617717002602413
9573027767123405
10133034331014411
11394305a7729192
1212b06b4035194b
1359301118382a8
1424bcc787bba31
15105a7dcc74c5b
hex78fe780b050b

133034331014411 has 2 divisors, whose sum is σ = 133034331014412. Its totient is φ = 133034331014410.

The previous prime is 133034331014401. The next prime is 133034331014437. The reversal of 133034331014411 is 114410133430331.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133034331014411 is a prime.

It is not a weakly prime, because it can be changed into another prime (133034331014401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66517165507205 + 66517165507206.

It is an arithmetic number, because the mean of its divisors is an integer number (66517165507206).

Almost surely, 2133034331014411 is an apocalyptic number.

133034331014411 is a deficient number, since it is larger than the sum of its proper divisors (1).

133034331014411 is an equidigital number, since it uses as much as digits as its factorization.

133034331014411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 32.

Adding to 133034331014411 its reverse (114410133430331), we get a palindrome (247444464444742).

The spelling of 133034331014411 in words is "one hundred thirty-three trillion, thirty-four billion, three hundred thirty-one million, fourteen thousand, four hundred eleven".