Base | Representation |
---|---|
bin | 11110001111111111010000… |
… | …101111010011011111011010 |
3 | 122110001111210021221200221111 |
4 | 132033333100233103133122 |
5 | 114414212123144231010 |
6 | 1150541441252530534 |
7 | 40010555022620602 |
oct | 3617772057233732 |
9 | 573044707850844 |
10 | 133040114055130 |
11 | 39432aa5043287 |
12 | 12b08095020a4a |
13 | 593082398c689 |
14 | 24bd266871c02 |
15 | 105aa2a80358a |
hex | 78ffd0bd37da |
133040114055130 has 32 divisors (see below), whose sum is σ = 241520566339584. Its totient is φ = 52761419395776.
The previous prime is 133040114055103. The next prime is 133040114055229. The reversal of 133040114055130 is 31550411040331.
It is a junction number, because it is equal to n+sod(n) for n = 133040114055092 and 133040114055101.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 33435537 + ... + 37202356.
It is an arithmetic number, because the mean of its divisors is an integer number (7547517698112).
Almost surely, 2133040114055130 is an apocalyptic number.
133040114055130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
133040114055130 is a deficient number, since it is larger than the sum of its proper divisors (108480452284454).
133040114055130 is a wasteful number, since it uses less digits than its factorization.
133040114055130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70639510.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 133040114055130 its reverse (31550411040331), we get a palindrome (164590525095461).
The spelling of 133040114055130 in words is "one hundred thirty-three trillion, forty billion, one hundred fourteen million, fifty-five thousand, one hundred thirty".
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