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1330402427 is a prime number
BaseRepresentation
bin100111101001100…
…0101010001111011
310102201101110000222
41033103011101323
510211040334202
6340003050255
744653143164
oct11723052173
93381343028
101330402427
11622a83042
1231167098b
13182821193
14c899676b
157bbe84a2
hex4f4c547b

1330402427 has 2 divisors, whose sum is σ = 1330402428. Its totient is φ = 1330402426.

The previous prime is 1330402421. The next prime is 1330402429. The reversal of 1330402427 is 7242040331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1330402427 - 212 = 1330398331 is a prime.

Together with 1330402429, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1330402396 and 1330402405.

It is not a weakly prime, because it can be changed into another prime (1330402421) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665201213 + 665201214.

It is an arithmetic number, because the mean of its divisors is an integer number (665201214).

Almost surely, 21330402427 is an apocalyptic number.

1330402427 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330402427 is an equidigital number, since it uses as much as digits as its factorization.

1330402427 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 26.

The square root of 1330402427 is about 36474.6819999846. The cubic root of 1330402427 is about 1099.8353546964.

Adding to 1330402427 its reverse (7242040331), we get a palindrome (8572442758).

The spelling of 1330402427 in words is "one billion, three hundred thirty million, four hundred two thousand, four hundred twenty-seven".