13304040140353 has 2 divisors, whose sum is σ = 13304040140354. Its totient is φ = 13304040140352.

The previous prime is 13304040140341. The next prime is 13304040140359. The reversal of 13304040140353 is 35304104040331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9579074520064 + 3724965620289 = 3095008^2 + 1930017^2 .

It is a cyclic number.

It is not a de Polignac number, because 13304040140353 - 2²⁵ = 13304006585921 is a prime.

It is a super-2 number, since 2×13304040140353² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13304040140359) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6652020070176 + 6652020070177.

It is an arithmetic number, because the mean of its divisors is an integer number (6652020070177).

Almost surely, 2^{13304040140353} is an apocalyptic number.

It is an amenable number.

13304040140353 is a deficient number, since it is larger than the sum of its proper divisors (1).

13304040140353 is an equidigital number, since it uses as much as digits as its factorization.

13304040140353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25920, while the sum is 31.

Adding to 13304040140353 its reverse (35304104040331), we get a palindrome (48608144180684).

The spelling of 13304040140353 in words is "thirteen trillion, three hundred four billion, forty million, one hundred forty thousand, three hundred fifty-three".