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13304040140341 is a prime number
BaseRepresentation
bin1100000110011001011010…
…0101100010111000110101
31202002212001102122221200001
43001212112211202320311
53220433133233442331
644143442555551301
72542120342221616
oct301462645427065
952085042587601
1013304040140341
11426a236907255
1215aa4b415b531
137567478210c2
1433dcc1969c0d
15181106899561
hexc1996962e35

13304040140341 has 2 divisors, whose sum is σ = 13304040140342. Its totient is φ = 13304040140340.

The previous prime is 13304040140311. The next prime is 13304040140353. The reversal of 13304040140341 is 14304104040331.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8317398320100 + 4986641820241 = 2883990^2 + 2233079^2 .

It is a cyclic number.

It is not a de Polignac number, because 13304040140341 - 25 = 13304040140309 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13304040140311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6652020070170 + 6652020070171.

It is an arithmetic number, because the mean of its divisors is an integer number (6652020070171).

Almost surely, 213304040140341 is an apocalyptic number.

It is an amenable number.

13304040140341 is a deficient number, since it is larger than the sum of its proper divisors (1).

13304040140341 is an equidigital number, since it uses as much as digits as its factorization.

13304040140341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 13304040140341 its reverse (14304104040331), we get a palindrome (27608144180672).

The spelling of 13304040140341 in words is "thirteen trillion, three hundred four billion, forty million, one hundred forty thousand, three hundred forty-one".