1330404134153 has 2 divisors, whose sum is σ = 1330404134154. Its totient is φ = 1330404134152.

The previous prime is 1330404134113. The next prime is 1330404134173. The reversal of 1330404134153 is 3514314040331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1112915282704 + 217488851449 = 1054948^2 + 466357^2 .

It is an emirp because it is prime and its reverse (3514314040331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1330404134153 - 2³² = 1326109166857 is a prime.

It is not a weakly prime, because it can be changed into another prime (1330404134113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665202067076 + 665202067077.

It is an arithmetic number, because the mean of its divisors is an integer number (665202067077).

Almost surely, 2^{1330404134153} is an apocalyptic number.

It is an amenable number.

1330404134153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330404134153 is an equidigital number, since it uses as much as digits as its factorization.

1330404134153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25920, while the sum is 32.

Adding to 1330404134153 its reverse (3514314040331), we get a palindrome (4844718174484).

The spelling of 1330404134153 in words is "one trillion, three hundred thirty billion, four hundred four million, one hundred thirty-four thousand, one hundred fifty-three".