Base | Representation |
---|---|
bin | 111101111100111011… |
… | …0101011111111110011 |
3 | 110201101211220001001011 |
4 | 1323321312223333303 |
5 | 4134431431203101 |
6 | 141041303451351 |
7 | 12416606556346 |
oct | 1737166537763 |
9 | 421354801034 |
10 | 133040881651 |
11 | 51471122567 |
12 | 2194b156b57 |
13 | c712ba0ca2 |
14 | 66212b445d |
15 | 36d9cd0751 |
hex | 1ef9dabff3 |
133040881651 has 2 divisors, whose sum is σ = 133040881652. Its totient is φ = 133040881650.
The previous prime is 133040881639. The next prime is 133040881669. The reversal of 133040881651 is 156188040331.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (156188040331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133040881651 - 211 = 133040879603 is a prime.
It is not a weakly prime, because it can be changed into another prime (133040881681) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66520440825 + 66520440826.
It is an arithmetic number, because the mean of its divisors is an integer number (66520440826).
Almost surely, 2133040881651 is an apocalyptic number.
133040881651 is a deficient number, since it is larger than the sum of its proper divisors (1).
133040881651 is an equidigital number, since it uses as much as digits as its factorization.
133040881651 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69120, while the sum is 40.
The spelling of 133040881651 in words is "one hundred thirty-three billion, forty million, eight hundred eighty-one thousand, six hundred fifty-one".
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