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133042213500120 = 2332511328111638639
BaseRepresentation
bin11110010000000001001101…
…111000000011010011011000
3122110001201012121102120001100
4132100001031320003103120
5114414230423124000440
61150542425451151400
740010661034613511
oct3620011570032330
9573051177376040
10133042213500120
1139433982132391
1212b08580145560
135930a99914a12
1424bd3c5615a08
15105aaeecab230
hex79004de034d8

133042213500120 has 192 divisors, whose sum is σ = 437766028502400. Its totient is φ = 35038818017280.

The previous prime is 133042213500073. The next prime is 133042213500137. The reversal of 133042213500120 is 21005312240331.

133042213500120 is a `hidden beast` number, since 1 + 3 + 3 + 0 + 4 + 22 + 13 + 500 + 120 = 666.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5611761 + ... + 17250399.

It is an arithmetic number, because the mean of its divisors is an integer number (2280031398450).

Almost surely, 2133042213500120 is an apocalyptic number.

133042213500120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133042213500120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (218883014251200).

133042213500120 is an abundant number, since it is smaller than the sum of its proper divisors (304723815002280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133042213500120 is a wasteful number, since it uses less digits than its factorization.

133042213500120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11639050 (or 11639043 counting only the distinct ones).

The product of its (nonzero) digits is 4320, while the sum is 27.

Adding to 133042213500120 its reverse (21005312240331), we get a palindrome (154047525740451).

The spelling of 133042213500120 in words is "one hundred thirty-three trillion, forty-two billion, two hundred thirteen million, five hundred thousand, one hundred twenty".