Base | Representation |
---|---|
bin | 11110010000000001111110… |
… | …100111000110101010011111 |
3 | 122110001210022120222000111202 |
4 | 132100001332213012222133 |
5 | 114414234111433003043 |
6 | 1150543042540110115 |
7 | 40011020223502313 |
oct | 3620017647065237 |
9 | 573053276860452 |
10 | 133043031141023 |
11 | 39434261722073 |
12 | 12b08769b3533b |
13 | 5930b9a1332c3 |
14 | 24bd462053b43 |
15 | 105ab4b96a1b8 |
hex | 79007e9c6a9f |
133043031141023 has 2 divisors, whose sum is σ = 133043031141024. Its totient is φ = 133043031141022.
The previous prime is 133043031141019. The next prime is 133043031141047. The reversal of 133043031141023 is 320141130340331.
It is a weak prime.
It is an emirp because it is prime and its reverse (320141130340331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133043031141023 - 22 = 133043031141019 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133043031041023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66521515570511 + 66521515570512.
It is an arithmetic number, because the mean of its divisors is an integer number (66521515570512).
Almost surely, 2133043031141023 is an apocalyptic number.
133043031141023 is a deficient number, since it is larger than the sum of its proper divisors (1).
133043031141023 is an equidigital number, since it uses as much as digits as its factorization.
133043031141023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 133043031141023 its reverse (320141130340331), we get a palindrome (453184161481354).
The spelling of 133043031141023 in words is "one hundred thirty-three trillion, forty-three billion, thirty-one million, one hundred forty-one thousand, twenty-three".
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