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133051097 is a prime number
BaseRepresentation
bin1111110111000…
…11001011011001
3100021100200210102
413323203023121
5233030113342
621111425145
73203626034
oct773431331
9307320712
10133051097
1169116293
12386851b5
132174647a
141395601b
15ba32832
hex7ee32d9

133051097 has 2 divisors, whose sum is σ = 133051098. Its totient is φ = 133051096.

The previous prime is 133051081. The next prime is 133051099. The reversal of 133051097 is 790150331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 132043081 + 1008016 = 11491^2 + 1004^2 .

It is a cyclic number.

It is not a de Polignac number, because 133051097 - 24 = 133051081 is a prime.

Together with 133051099, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (133051099) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66525548 + 66525549.

It is an arithmetic number, because the mean of its divisors is an integer number (66525549).

Almost surely, 2133051097 is an apocalyptic number.

It is an amenable number.

133051097 is a deficient number, since it is larger than the sum of its proper divisors (1).

133051097 is an equidigital number, since it uses as much as digits as its factorization.

133051097 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2835, while the sum is 29.

The square root of 133051097 is about 11534.7777178409. Note that the first 4 decimals coincide. The cubic root of 133051097 is about 510.5122330131.

The spelling of 133051097 in words is "one hundred thirty-three million, fifty-one thousand, ninety-seven".