Base | Representation |
---|---|
bin | 1100000110011101110110… |
… | …1010000011000100011111 |
3 | 1202002222010112022020211122 |
4 | 3001213131222003010133 |
5 | 3220443104010044241 |
6 | 44144201152241155 |
7 | 2542162031151035 |
oct | 301473552030437 |
9 | 52088115266748 |
10 | 13305232503071 |
11 | 426a798976aa3 |
12 | 15aa7875401bb |
13 | 7568a7870292 |
14 | 33dd9606c555 |
15 | 1811763c704b |
hex | c19dda8311f |
13305232503071 has 2 divisors, whose sum is σ = 13305232503072. Its totient is φ = 13305232503070.
The previous prime is 13305232503029. The next prime is 13305232503091. The reversal of 13305232503071 is 17030523250331.
13305232503071 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (17030523250331) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13305232503071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13305232503001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6652616251535 + 6652616251536.
It is an arithmetic number, because the mean of its divisors is an integer number (6652616251536).
Almost surely, 213305232503071 is an apocalyptic number.
13305232503071 is a deficient number, since it is larger than the sum of its proper divisors (1).
13305232503071 is an equidigital number, since it uses as much as digits as its factorization.
13305232503071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56700, while the sum is 35.
The spelling of 13305232503071 in words is "thirteen trillion, three hundred five billion, two hundred thirty-two million, five hundred three thousand, seventy-one".
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