Base | Representation |
---|---|
bin | 11110010000001010110011… |
… | …110101010001110100100111 |
3 | 122110002200210110121100021021 |
4 | 132100022303311101310213 |
5 | 114414413022034440113 |
6 | 1150551251530232011 |
7 | 40011504221361232 |
oct | 3620126365216447 |
9 | 573080713540237 |
10 | 133052513983783 |
11 | 394382885211a9 |
12 | 12b0a575885607 |
13 | 5931a4b93c174 |
14 | 24bdac1636419 |
15 | 105b00422148d |
hex | 7902b3d51d27 |
133052513983783 has 2 divisors, whose sum is σ = 133052513983784. Its totient is φ = 133052513983782.
The previous prime is 133052513983757. The next prime is 133052513983787. The reversal of 133052513983783 is 387389315250331.
It is a strong prime.
It is an emirp because it is prime and its reverse (387389315250331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133052513983783 - 29 = 133052513983271 is a prime.
It is a super-2 number, since 2×1330525139837832 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133052513983787) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66526256991891 + 66526256991892.
It is an arithmetic number, because the mean of its divisors is an integer number (66526256991892).
Almost surely, 2133052513983783 is an apocalyptic number.
133052513983783 is a deficient number, since it is larger than the sum of its proper divisors (1).
133052513983783 is an equidigital number, since it uses as much as digits as its factorization.
133052513983783 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48988800, while the sum is 61.
The spelling of 133052513983783 in words is "one hundred thirty-three trillion, fifty-two billion, five hundred thirteen million, nine hundred eighty-three thousand, seven hundred eighty-three".
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