Base | Representation |
---|---|
bin | 11110010000001100011000… |
… | …101110001110010111010111 |
3 | 122110002212011102121212001222 |
4 | 132100030120232032113113 |
5 | 114414430003344232211 |
6 | 1150552131513440555 |
7 | 40011564163560656 |
oct | 3620143056162727 |
9 | 573085142555058 |
10 | 133054206633431 |
11 | 39438a76a23a06 |
12 | 12b0a96871015b |
13 | 5931c5b513bc5 |
14 | 24bdc0236719d |
15 | 105b0a2b221db |
hex | 790318b8e5d7 |
133054206633431 has 2 divisors, whose sum is σ = 133054206633432. Its totient is φ = 133054206633430.
The previous prime is 133054206633329. The next prime is 133054206633463. The reversal of 133054206633431 is 134336602450331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133054206633431 is a prime.
It is a super-4 number, since 4×1330542066334314 (a number of 58 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133054206633031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66527103316715 + 66527103316716.
It is an arithmetic number, because the mean of its divisors is an integer number (66527103316716).
Almost surely, 2133054206633431 is an apocalyptic number.
133054206633431 is a deficient number, since it is larger than the sum of its proper divisors (1).
133054206633431 is an equidigital number, since it uses as much as digits as its factorization.
133054206633431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1399680, while the sum is 44.
The spelling of 133054206633431 in words is "one hundred thirty-three trillion, fifty-four billion, two hundred six million, six hundred thirty-three thousand, four hundred thirty-one".
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