Base | Representation |
---|---|
bin | 11110010000001101001001… |
… | …111000111011011111100101 |
3 | 122110002221021220210121020122 |
4 | 132100031021320323133211 |
5 | 114414433201032221201 |
6 | 1150552345422011325 |
7 | 40011623501200466 |
oct | 3620151170733745 |
9 | 573087256717218 |
10 | 133055031523301 |
11 | 3943935a614978 |
12 | 12b0ab58a16b45 |
13 | 593206039cb14 |
14 | 24bdc7db30d6d |
15 | 105b100263e1b |
hex | 790349e3b7e5 |
133055031523301 has 2 divisors, whose sum is σ = 133055031523302. Its totient is φ = 133055031523300.
The previous prime is 133055031523261. The next prime is 133055031523391. The reversal of 133055031523301 is 103325130550331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 91907232754276 + 41147798769025 = 9586826^2 + 6414655^2 .
It is an emirp because it is prime and its reverse (103325130550331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133055031523301 - 218 = 133055031261157 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133055031523391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66527515761650 + 66527515761651.
It is an arithmetic number, because the mean of its divisors is an integer number (66527515761651).
Almost surely, 2133055031523301 is an apocalyptic number.
It is an amenable number.
133055031523301 is a deficient number, since it is larger than the sum of its proper divisors (1).
133055031523301 is an equidigital number, since it uses as much as digits as its factorization.
133055031523301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60750, while the sum is 35.
The spelling of 133055031523301 in words is "one hundred thirty-three trillion, fifty-five billion, thirty-one million, five hundred twenty-three thousand, three hundred one".
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