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1330657012543 is a prime number
BaseRepresentation
bin10011010111010001010…
…101101010101100111111
311201012122202221001101011
4103113101111222230333
5133300141143400133
62455143445500051
7165064630661605
oct23272125525477
94635582831334
101330657012543
114733682144a1
12195a82411627
139863262a351
1448592d7b875
152493057e6cd
hex135d156ab3f

1330657012543 has 2 divisors, whose sum is σ = 1330657012544. Its totient is φ = 1330657012542.

The previous prime is 1330657012511. The next prime is 1330657012579. The reversal of 1330657012543 is 3452107560331.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1330657012543 - 25 = 1330657012511 is a prime.

It is a super-3 number, since 3×13306570125433 (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1330657012496 and 1330657012505.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1330657015543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665328506271 + 665328506272.

It is an arithmetic number, because the mean of its divisors is an integer number (665328506272).

Almost surely, 21330657012543 is an apocalyptic number.

1330657012543 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330657012543 is an equidigital number, since it uses as much as digits as its factorization.

1330657012543 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 226800, while the sum is 40.

The spelling of 1330657012543 in words is "one trillion, three hundred thirty billion, six hundred fifty-seven million, twelve thousand, five hundred forty-three".