Base | Representation |
---|---|
bin | 111101111101110111… |
… | …0001010101100000111 |
3 | 110201111000211022011201 |
4 | 1323323232022230013 |
5 | 4140012440440003 |
6 | 141044343043331 |
7 | 12420440025652 |
oct | 1737356125407 |
9 | 421430738151 |
10 | 133072202503 |
11 | 51487875369 |
12 | 21959740547 |
13 | c719519236 |
14 | 6625508899 |
15 | 36dc91ab1d |
hex | 1efbb8ab07 |
133072202503 has 2 divisors, whose sum is σ = 133072202504. Its totient is φ = 133072202502.
The previous prime is 133072202491. The next prime is 133072202507. The reversal of 133072202503 is 305202270331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133072202503 - 29 = 133072201991 is a prime.
It is a super-3 number, since 3×1330722025033 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133072202507) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66536101251 + 66536101252.
It is an arithmetic number, because the mean of its divisors is an integer number (66536101252).
Almost surely, 2133072202503 is an apocalyptic number.
133072202503 is a deficient number, since it is larger than the sum of its proper divisors (1).
133072202503 is an equidigital number, since it uses as much as digits as its factorization.
133072202503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7560, while the sum is 28.
Adding to 133072202503 its reverse (305202270331), we get a palindrome (438274472834).
The spelling of 133072202503 in words is "one hundred thirty-three billion, seventy-two million, two hundred two thousand, five hundred three".
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