Base | Representation |
---|---|
bin | 111101111101111111… |
… | …1011111000110001101 |
3 | 110201111100100221221021 |
4 | 1323323333133012031 |
5 | 4140020121230131 |
6 | 141045024234141 |
7 | 12420523435141 |
oct | 1737377370615 |
9 | 421440327837 |
10 | 133076742541 |
11 | 5148a396366 |
12 | 2195b16b951 |
13 | c71a448852 |
14 | 6625d6b221 |
15 | 36dd015e11 |
hex | 1efbfdf18d |
133076742541 has 2 divisors, whose sum is σ = 133076742542. Its totient is φ = 133076742540.
The previous prime is 133076742503. The next prime is 133076742551. The reversal of 133076742541 is 145247670331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 129855726025 + 3221016516 = 360355^2 + 56754^2 .
It is an emirp because it is prime and its reverse (145247670331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133076742541 - 231 = 130929258893 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133076742551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66538371270 + 66538371271.
It is an arithmetic number, because the mean of its divisors is an integer number (66538371271).
Almost surely, 2133076742541 is an apocalyptic number.
It is an amenable number.
133076742541 is a deficient number, since it is larger than the sum of its proper divisors (1).
133076742541 is an equidigital number, since it uses as much as digits as its factorization.
133076742541 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 423360, while the sum is 43.
The spelling of 133076742541 in words is "one hundred thirty-three billion, seventy-six million, seven hundred forty-two thousand, five hundred forty-one".
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