Base | Representation |
---|---|
bin | 1100000110101000011101… |
… | …0100111110001000101111 |
3 | 1202010020110220200120222101 |
4 | 3001222013110332020233 |
5 | 3221014421222321214 |
6 | 44145351440555531 |
7 | 2542322414650531 |
oct | 301520724761057 |
9 | 52106426616871 |
10 | 13308079104559 |
11 | 4270a19793908 |
12 | 15ab240922ba7 |
13 | 756c3c535a65 |
14 | 340186143851 |
15 | 181291269774 |
hex | c1a8753e22f |
13308079104559 has 2 divisors, whose sum is σ = 13308079104560. Its totient is φ = 13308079104558.
The previous prime is 13308079104547. The next prime is 13308079104581. The reversal of 13308079104559 is 95540197080331.
13308079104559 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13308079104559 - 219 = 13308078580271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13308079104059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6654039552279 + 6654039552280.
It is an arithmetic number, because the mean of its divisors is an integer number (6654039552280).
Almost surely, 213308079104559 is an apocalyptic number.
13308079104559 is a deficient number, since it is larger than the sum of its proper divisors (1).
13308079104559 is an equidigital number, since it uses as much as digits as its factorization.
13308079104559 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4082400, while the sum is 55.
The spelling of 13308079104559 in words is "thirteen trillion, three hundred eight billion, seventy-nine million, one hundred four thousand, five hundred fifty-nine".
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