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133100001100 = 225211193362597
BaseRepresentation
bin111101111110101100…
…0001101011101001100
3110201112222010121200101
41323331120031131030
54140042100013400
6141051214540444
712421225225303
oct1737530153514
9421488117611
10133100001100
11514a1531910
1221966b07724
13c722200201
1466290a343a
1536e00ac56a
hex1efd60d74c

133100001100 has 72 divisors (see below), whose sum is σ = 315252041328. Its totient is φ = 48374188800.

The previous prime is 133100001079. The next prime is 133100001121. The reversal of 133100001100 is 1100001331.

It is an interprime number because it is at equal distance from previous prime (133100001079) and next prime (133100001121).

It is a super-2 number, since 2×1331000011002 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (10).

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2095002 + ... + 2157598.

It is an arithmetic number, because the mean of its divisors is an integer number (4378500574).

Almost surely, 2133100001100 is an apocalyptic number.

133100001100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133100001100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (157626020664).

133100001100 is an abundant number, since it is smaller than the sum of its proper divisors (182152040228).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133100001100 is a wasteful number, since it uses less digits than its factorization.

133100001100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 64555 (or 64548 counting only the distinct ones).

The product of its (nonzero) digits is 9, while the sum is 10.

Adding to 133100001100 its reverse (1100001331), we get a palindrome (134200002431).

It can be divided in two parts, 13310000 and 1100, that multiplied together give a square (14641000000 = 1210002).

The spelling of 133100001100 in words is "one hundred thirty-three billion, one hundred million, one thousand, one hundred".

Divisors: 1 2 4 5 10 11 20 22 25 44 50 55 100 110 220 275 550 1100 1933 3866 7732 9665 19330 21263 38660 42526 48325 62597 85052 96650 106315 125194 193300 212630 250388 312985 425260 531575 625970 688567 1063150 1251940 1377134 1564925 2126300 2754268 3129850 3442835 6259700 6885670 13771340 17214175 34428350 68856700 121000001 242000002 484000004 605000005 1210000010 1331000011 2420000020 2662000022 3025000025 5324000044 6050000050 6655000055 12100000100 13310000110 26620000220 33275000275 66550000550 133100001100