Base | Representation |
---|---|
bin | 11110010000110111000011… |
… | …101111000110110000101011 |
3 | 122110021020102121210110101212 |
4 | 132100313003233012300223 |
5 | 114421202323003110243 |
6 | 1151025150233503335 |
7 | 40015105465165163 |
oct | 3620670357066053 |
9 | 573236377713355 |
10 | 133100025441323 |
11 | 394564494a6496 |
12 | 12b17815271b4b |
13 | 5936380c61855 |
14 | 24c210b6595a3 |
15 | 105c3853a0318 |
hex | 790dc3bc6c2b |
133100025441323 has 2 divisors, whose sum is σ = 133100025441324. Its totient is φ = 133100025441322.
The previous prime is 133100025441283. The next prime is 133100025441413. The reversal of 133100025441323 is 323144520001331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133100025441323 - 210 = 133100025440299 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 133100025441323.
It is not a weakly prime, because it can be changed into another prime (133100025441923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66550012720661 + 66550012720662.
It is an arithmetic number, because the mean of its divisors is an integer number (66550012720662).
Almost surely, 2133100025441323 is an apocalyptic number.
133100025441323 is a deficient number, since it is larger than the sum of its proper divisors (1).
133100025441323 is an equidigital number, since it uses as much as digits as its factorization.
133100025441323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 32.
Adding to 133100025441323 its reverse (323144520001331), we get a palindrome (456244545442654).
The spelling of 133100025441323 in words is "one hundred thirty-three trillion, one hundred billion, twenty-five million, four hundred forty-one thousand, three hundred twenty-three".
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