133100117 has 2 divisors, whose sum is σ = 133100118. Its totient is φ = 133100116.

The previous prime is 133100087. The next prime is 133100153. The reversal of 133100117 is 711001331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 105966436 + 27133681 = 10294^2 + 5209^2 .

It is a cyclic number.

It is not a de Polignac number, because 133100117 - 2²² = 128905813 is a prime.

It is a super-2 number, since 2×133100117² = 35431282290827378, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 133100095 and 133100104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133100167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66550058 + 66550059.

It is an arithmetic number, because the mean of its divisors is an integer number (66550059).

Almost surely, 2^133100117 is an apocalyptic number.

It is an amenable number.

133100117 is a deficient number, since it is larger than the sum of its proper divisors (1).

133100117 is an equidigital number, since it uses as much as digits as its factorization.

133100117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 63, while the sum is 17.

The square root of 133100117 is about 11536.9024005580. The cubic root of 133100117 is about 510.5749213023.

Adding to 133100117 its reverse (711001331), we get a palindrome (844101448).

The spelling of 133100117 in words is "one hundred thirty-three million, one hundred thousand, one hundred seventeen".