Base | Representation |
---|---|
bin | 111101111110101100… |
… | …0111110000101101101 |
3 | 110201112222111201221012 |
4 | 1323331120332011231 |
5 | 4140042122402201 |
6 | 141051223115005 |
7 | 12421230015125 |
oct | 1737530760555 |
9 | 421488451835 |
10 | 133100200301 |
11 | 514a1658542 |
12 | 21966ba2a65 |
13 | c72226ca93 |
14 | 6629115c85 |
15 | 36e00eb5bb |
hex | 1efd63e16d |
133100200301 has 2 divisors, whose sum is σ = 133100200302. Its totient is φ = 133100200300.
The previous prime is 133100200297. The next prime is 133100200403. The reversal of 133100200301 is 103002001331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 84739792201 + 48360408100 = 291101^2 + 219910^2 .
It is an emirp because it is prime and its reverse (103002001331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133100200301 - 22 = 133100200297 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133100200501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66550100150 + 66550100151.
It is an arithmetic number, because the mean of its divisors is an integer number (66550100151).
Almost surely, 2133100200301 is an apocalyptic number.
It is an amenable number.
133100200301 is a deficient number, since it is larger than the sum of its proper divisors (1).
133100200301 is an equidigital number, since it uses as much as digits as its factorization.
133100200301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 133100200301 its reverse (103002001331), we get a palindrome (236102201632).
The spelling of 133100200301 in words is "one hundred thirty-three billion, one hundred million, two hundred thousand, three hundred one".
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